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Aplicando as Leis de Newton (II)

Borges e Nicolau

Leis de Newton

Exercício 3: resolução

PFD (A): T - 10 = 2,0.a  (1)
PFD (B): 30 – T = 3,0.a (2)
(1) + (2): 30 - 10 = (2,0 + 3,0).a => a = 4,0 m/s²
De (1): T – 10 = 2,0.4,0 => T = 18 N
 
Respostas: 4,0 m/s²; 18 N

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