Lei de Coulomb (II)
Borges e Nicolau
Exercícios de Revisão
Revisão/Ex 5: resolução
Cargas Q de mesmo sinal:
T.sen 30º = k.Q2/D2 e T.cos 30º = P => tg 30º = k.Q2/P.D2 (1)
D = 2l+2l.sen 30º => D = 3l
Cargas q de sinais opostos:
T.sen 30º = k.q2/d2 e T.cos 30º = P => tg 30º = k.q2/P.d2 (2)
d = 2l-2l.sen 30º => d = l
(1) = (2) => Q2/D2 = q2/d2 => IQ/qI = D/d = 3l/l => IQ/qI = 3
Resposta: 3
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